Chemistry Experiment Form 6

chemistry experiment form 6
Question: chemistry help please help!!!!!!!!?

One of the steps in the commercial process for converting ammonia to nitric acid is the conversion of NH3 to NO.
4 NH3(g) + 5 O2(g) → 4 NO(g) + 6 H2O(g)
In a certain experiment, 3.50 g of NH3 reacts with 6.09 g of O2.
(a) Which is the limiting reactant?
1
NH3
O2

(b) How many grams of NO form?
WebAssign will check your answer for the correct number of significant figures. 2 g

(c) How many grams of the excess reactant remains after the limiting reactant is completely consumed?
3 g

Answer: 1
NH3 ==> 14 + 3 = 17
4*17 = 68
3.50 / 68 ≈ 0.0514706
O2 ==> 2*16 = 32
5*32 = 160
6.09 / 160 ≈ 0.0380625

2
NO ==> 30
4*30 = 120
0.0380625*120 ≈ 4.5675 g ≈ 4.57 g

3
68(0.0514706 – 0.0380625) ≈ 0.91175 g ≈ 0.912 g

Lec 6 | MIT 3.091 Introduction to Solid State Chemistry


Leave a Reply

Security Code:

Best Science Experiment Kits
Our Science Experiments Blogs: